Question

the sum of three prime numbers is 100 if one of them exceeds another by 36 then one of the numbers is

Answer 1

I hope it will help you

As we know that the sum of three odd numbers cannot be even i.e. one of the prime is even or 22 let one of the other prime is p1 then the third prime is p1+36

now according to question
2+p1+p1+36=100

2p1=62

p1=31

Hence, the primes are

2,31,67

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