Question

The sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the number is

Answer 1

Step-by-step explanation:

Let the three prime numbers be = x , y , z .

= x + y + z = 100 ⸻➤(1 )

• given condition is ( one if them exceeds another by 36 )

Let that number be z = y + 36

• now put the value of z in equation ( 1 )

= x + y + y + 36 = 100

= x + 2y = 100 - 36

= x + 2y = 64

let x = 2 ( smallest prime number )

now finding the value of y and z

2 + 2 y = 64

2y = 64 - 2 = 62

y = 31

z = y + 36

= 31 + 36

= 67

hope it helps you..

Answer 2

Answer:

67 , 31 , 2

Step-by-step explanation:

x,x+36,y

2x+36+y = 100

2x+y=64

x = 31 , y = 2 is only possible

so 31 , 67 , 2