Question

The sum of three prime numbers is 100 if one of them exceeds another by 36 then one of the numbers is

Answer 1

the answer is

let the no. 2x

36 + 2x = 100

2x = 100 _ 36 = 64

x = 64 * 2= 32

Answer 2

Answer:

The three numbers are 67,31,2.

Step-by-step explanation:

All 67,31,2 are whole numbers and when we add-

= 67+31+2 = 100

And when we subtract-

= 67-31 = 36

Hence, your answer is 67,31,2.

Hope this answer helped you : )