Math, asked by jaypalsinh9103, 11 months ago

The sum of three prime numbers is 100. If one of them exceeds another by 36, then one of the numbers is: a. 7 b. 29 c. 41 d. 67

Answers

Answered by brunoconti
4

Answer:

Step-by-step explanation:

since the Only even prime number is 2 and since the sum is 100, then one of the numbers must be 2 and therefore the sum of the other two should be 98. thus x + y = 98 and x - y = 36. if we sum the equations we get 2x = 134 and x = 67 and y = 31.

the numbers are 2 , 31 and 67.

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