The sum of three prime numbers is 100. The difference of two of them is 24. What are the numbers? Show proper explaination.
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let the 3 prime number be x, y ,z
then
x+y+z=100...(1)
and
x-y=24....(2)
adding (1) and (2)
2x+z=124
z=124-2x....(3)
subtracting (1) from (2)
2y+z=76
z=76-2y....(4)
From (3) and (4) we can see that z is even [ even - even = even, any number when multiplied by 2 gives even number]
The only number that is even and prime is '2'
so z =2
so we get
2x+2=124
2x=122
x=61
and
2y+2=76
2y=74
y=37
so the numbers are 2 , 37, 61
then
x+y+z=100...(1)
and
x-y=24....(2)
adding (1) and (2)
2x+z=124
z=124-2x....(3)
subtracting (1) from (2)
2y+z=76
z=76-2y....(4)
From (3) and (4) we can see that z is even [ even - even = even, any number when multiplied by 2 gives even number]
The only number that is even and prime is '2'
so z =2
so we get
2x+2=124
2x=122
x=61
and
2y+2=76
2y=74
y=37
so the numbers are 2 , 37, 61
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