The sum of three prime numbers is 80.The difference of two if them is 4.Find the numbers
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According to the question, we have to find three prime numbers the sum of which will be 80 and also the difference of two of them will be 4.
Now since it is clearly mentioned that the sum of three no.s will be 80 so none of the prime numbers will exceed 80.
Therefore the prime numbers from 0 to 80 are as follows: 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79.
The next hint to solve this question is any two prime numbers must have a difference of 4. So we can see the prime numbers 2, 37 and 41 sum upto 80 and the difference of 37 and 41 is 4.
∵ The three prime numbers are 2, 37 and 41. [Ans]
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