The sum of three shares x, y, z is Rs.936, if 3x = 4y = 62. then what are the shares of yand 2? (a) 208, 312, 416 októ, 312, 208 (C) 312, 208, 416 (d) 416, 208, 312
Answers
Answer:
Solution 4
a) 137 and – 354
= 137 + (-354)
= -217
b) – 52 and 52
= -52 + 52
= 0
c) – 312, 39 and 192
= -312 + 39 + 192
= -81
d) – 50, – 200 and 300
= -50 + (-200) + (300)
= 50
Step-by-step explanation:
first one is 137 and minus 2 minus 354 so as it is minus so it will be 137 minus 354 okay so what you have to do in this case to find the answer easily is to first of all subtract 137 from minus 354 and then put a minus sign so 354 354 minus 100 i'm sorry 354 minus 137 will give you 217 but now as it is the other way around actually we'll just put a minus sign so this is the answer the first one let's go to the second one the second one is minus 52 and 52. now as both are additive inverse of each other that is the only difference is their sign therefore adding them will give you the answer directly zero let's move to the third one so in third one we have three so that is minus 312 39 and 192. first of all add both the positives that is 192 plus 39 so your answer will come out to be 231 and this is minus 312 plus 239 again use the same trick subtract 231 first from theta and 12 so do 312 minus 2 okay 312 minus 231 this will give you 81 but as it is actually the other way round you just put a negative sign over here let's move on to the last question the d part the d part is minus 50 minus 200 and 300 okay so again what you do is first of all add both of them and then put a minus sign so it should be minus 250 plus 300 so this time it's just the 300 is because it would be 300 minus 250 for which the answer will come out to be 50.