The sum of three sides of a triangle is 16 3/5 CM. If two of it's measure 5 7/10cm and 6 3/4cm respectively, then the length of the third side is
Answers
Question
The sum of three sides of a triangle is 163/5 CM. If two of it's measure 57/10cm and 63/4cm respectively, then the length of the third side is ?
Solution
Given:-
- The sum of three sides of a triangle is 163/5 CM.
- Two side are 57/10 cm & 63/4 cm.
Find:-
- Length of third sides
Explanation
We know,
Sum of all side of triangle be perimeter of triangle .
So,
we can say that 163/5 cm be perimeter of triangle ∆ABC
Let,
- AB = 57/10 cm
- BC = 63/4 cm
CA be the Third side of ∆ABC
★ perimeter of triangle = Sum of all side of triangle
==> 163/5 = AB + BC + CA
==> 163/5 = 57/10 + 63/4 + CA
==> CA = 163/5 - [ 57/10 + 63/4 ]
==> CA = 163/5 - [ (114+315)/20 ]
==> CA = 163/5 - [ 429/20 ]
==> CA = 163/5 - 429/20
==> CA = (652 - 429 )/20
==> CA = 223/20
Hence
- Third side will be of ∆ABC = 223/20 cm.
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Verification
We prove here, Sum of all sides ∆ABC will be = 163/5 cm
So,
==> 163/5 = 57/10 + 63/4 + 223/20
==> 163/5 = (114 + 315 + 223)/20
==> 163/5 = 652/20
==> 163/5 = 163/5
LH.S. = R.H.S.
That's proved.
Here, Sum of all side = 163/5 cm
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✬ Length of third side = 10.9 cm
Step-by-step explanation:
Given:
- Sum of all three sides of triangle is 163/5 cm.
- Measure of first side is 57/10 cm.
- Measure of second side is 64/4 cm.
To Find:
- What is the length of third side of the triangle ?
Solution: Let ABC be a triangle where
- AB = 57/10 cm = 5.7 cm
- BC = 64/4 cm = 16 cm
- CA = ?
★ Perimeter of triangle = Sum of its all sides ★
But perimeter given is 163/5 cm = 32.6 cm
A/q
(AB + BC + CA) cm = 32.6 cm
(5.7 + 16 + CA) cm = 32.6 cm
(21.7 + CA) cm = 32.6 cm
CA = (32.6 – 21.7) cm
CA = 10.9 cm
Hence, the length of third side of third side CA of triangle ABC is of 10.9 cm or 109/10 cm
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★ ChEck ★
➽ AB + BC + CA = 32.6
➽ 5.7 + 16 + 10.9 = 32.6
➽ 32.6 cm = 32.6 cm { LHS = RHS }
Since, 32.6 cm = 326/10 = 163/5 cm