The sum of three successive numbers in an ap is 192 then the numbers are
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Step-by-step explanation:
let three consecutive numbers be
a,a-d,a+d
According to given condition.a+a-d+a+d = 18
3a= 18
a= 6
According to next given condition.
a(a+d)(a-d) = 192
a(a-d)^2 = 192
(a-d)^2 = 32
a^2 +d^2 -2ad = 32
36 + d^2 - 12d = 32
d^2 -12d = -4
d^2 +d = 1/3.......(1)
hope it helps you
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