Question

The sum of three. Term of an AP is21 and product of the first and third term exceed the second term by 6, find three terms

Answer 1

Let three terms are a-d, a, a+d
sum= a-d+a+a+d=21
3a=21
a=7
now terms are 7-d, 7, 7+d
now
(7-d)(7+d) - 7 = 6
49 - d^2 = 13
d^2= 36
d= +-6
u can find all three terms by putting values which comes
1, 7, 13. or. 13,7,1