Question

The sum of three terms of an AP
21 and the Produt of
the first and the third trims exceeds the second term by 6, find three Terms​

Answer 1

let the three terms be a-d, a, a+d respectively

by given condition,

a-d+a+a+d=21

3a=21

a=21/3

a=7

by 2nd condition,

(a-d)(a+d)=6+a

a2-d2=6+a

(7)^2-d2=6(7)

49-42=d2

7=d2

d=root7 or -root7

a-d=7-root7 or 7+root7

a=7

a+d=7-root7 or 7+root7