Question

The sum of three terms of an arithmetic sequence is 36 and their product is 1140 find the term

Answer 1

Answer:

your answer is down

Step-by-step explanation:

let the A.P. be (a-b),(a),(a+b)

According to question a - b + a + a + b = 36

3a = 36

a = 12

now (a-b)(a+b)a = 1140

(a*a - b*b)a = 1140

(12*12 - b*b)12 = 1140

(144 - b*b) = 1140/12

114 - b*b = 95

114 - 95 = b*b

19 = b*b

√19 = b

A.P. = (12 -√19 ), 12 , (12 + √19)

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