Math, asked by Anonymous, 1 year ago

The sum of three terms which are in an AP is 33, if the product of first term and third term exceeds the second term by 29 find the AP.

Answers

Answered by shalini75
5
Hey .. I hope my soln will satisfied you....
Attachments:

shalini75: This is the consecutive term in the AP
shalini75: I m sry ..what do u mean by -d
Answered by siddhartharao77
9
Let the three terms be a-d, a, a+d.

Given that sum of three terms which are in AP = 33.

a + a - d + a + d = 33

3a = 33

a = 11.


Given that the product of the first term and third term exceeds the second term.

(a - d)(a + d) = 29 + a  ------- (2)

Substitute a = 11 in (2), we get

(11 - d)(11 + d) = 29 + 11

11^2 - d^2 = 40

121 - d^2 = 40

-d^2 = -81 

d = 9 (or) -9.


When d = 9,

a = 11

a - d = 11 - 9 = 2

a + d = 11 + 9 = 20.


When d = -9

a = 11

a - d = 11 - (-9) = 20

a + d = 11 + (-9) = 2.


Therefore the AP is 20,11,2 (or) 2,11,20.


Hope this helps!

siddhartharao77: U can take a,a-d,a+2d (or) a+2d,a,a+d (or) any value its ur wish. Since it is AP.
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