Question

the sum of three times the age of the son and age of his father is 110.if three times the age of his father is added to age of son we get 170 .then what is the sum of their ages find their ages​

Answer 1

Step-by-step explanation:

Write the two descriptions as equations:

110 = f + 3*s — eq. 1

170 = s + 3*f — eq. 2

f = 110 - (3 *s) — eq. 1 rearranged

170 = s +3*(110 - 3*s) — eq. 1 plugged into eq. 2

170 = s +( 330 - 9*s) — eq. 2 reduced

170 = 330 - 8*s — eq. 2 reduced

8*s = = 330 - 170 — eq. 2 reduced

8*s = 160 — eq. 2 reduced

s = 160 / 8 — eq. 2 reduced

s = 20 — eq. 2 reduced - the son is 20 yrs old.

110 = f + 3 * 20 — plugging son’s age into eq. 1

f = 110 - 60 — eq. 1 reduced

f = 50 — eq. 1 reduced — the father is 50 yrs old

Answer 2

Answer:

AGE OF FATHER = 50yrs

AGE OF SON       = 20yrs

Step-by-step explanation:

LET THE AGE OF THE FATHER BE x

AND

AGE OF SON BE y

SO,

A.T.Q.,

3y+x = 110    (eq. 1)

3x+y = 170     (eq. 2)

SO,

IN EQUATION 2,

3x+y = 170

x = (170 -y)/3

SO,

SUBSTITUTING THE VALUE OF x IN THE EQUATION 1,

WE GET,

3y+x=110

3y+[(170-y)/3]=110

(170+8y)/3 = 110

170+8y = 110*3

8y = 330-170

8y = 160

y = 20

SO,

x = (170-y)/3

  = (170-20)/3

  = 150/3

  = 50

SO,

AGE OF FATHER = x = 50yrs

AGE OF SON       = y = 20yrs

I HOPE YOU UNDERSTOOD THE QUESTION!!!

                         !!!JAI SHREE KRISHNA!!!