Question

the sum of threevconsecutive numbers os 138 then the greastest of these. no. is​

Answer 1

Answer:

47

Step-by-step explanation:

let the numbers be x ;(x+1) ;(x+2)

x+x+1+x+2 = 138

or,   3x+3   = 138

or,      3x    = 135

or,        x    = 135/3 = 45

hence the biggest number is = (45+2) = 47