The sum of trice the first number,second number and twice the third number is 5.if trice the second number is subracted from the sum of first number and trice the third we get 2. if the third number is subractedfrom the sum of twice the first, yrice the second,we get 1 .find the numbers
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Answer:
Numbers are 22 and 40.
Step-by-step explanation:
Let us assume, the two numbers are x and y.
Given:
3x + y = 142 ------------1
And also given:
4x – y = 138
y = 4x – 138 --------------2
Substitute the value of y from eqn 2 in eqn 1
3x + 4x – 138 = 142
7x - 138 = 142
7x = 142 + 138
7x = 280
x = 40
Therefore, y = (4 * 40) – 138 = 22
The two numbers are 40 and 22
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