Question

the sum of twice a number and 4 is 80 ,find the number​

Answer 1

$\bold{ \large{ \underline{ \underline{ \: \: \: Answer \: \: \: }}}}$

$\to$ Required number = 38

$\bold{ \large{ \underline{ \underline{ \: \: \: Explanation \: \: \: }}}}$

Let the unknown number be x

$\to$ First number = 2x

$\to$ Second number = 4

$\underline{\bold{ \: According \: to \: the \: question \: , \: \: }}$

$\to$ First number + Second number = 80

$\to$ 2x + 4 = 80

$\to$ 2x = 80 - 4

$\to$ 2x = 76

$\to$ x = 76 ÷ 2

$\to$ x = 38

Therefore , 38 is the required number

Answer 2

HERE IS YOUR ANSWER IN IMAGE❣️❣️✔️✔️✌️✌️