The sum of twice a number and 5 is less than the sum of one third of the number and 6
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Answer:
number [=33/7
Step-by-step explanation:
Let number =x
twice of the number=2x
given,
2x=5-1/3x+6
2x+1/3x=5+6
6x+x/3 = 11
7x/3 =11
7x=33
x=33/7
VERIFICATION
2x=33/7x2
66/7
from equation
2x = 5-1/3x +6
66/7 = 5-11/7+6
66/7 = 35-11+42/7
66/7 = 77-11/7
66/7 = 66/7
therefore, LHS=RHS
number =33/7
twice of the number = 66/7 hence proved
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