The sum of twice the base and thrice the exponent of (-20)²⁰
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Find two numbers such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.
Solution:
Given : two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2
To find : the two numbers
Let x and y be the two numbers required.
A/q
⇒2x+3y=92 ........(1)
⇒4x−7y=2 ........(2)
multiply the first equation by 2 , and subtract eqn (1) from eqn (2)
4x+6y=184
−(4x−7y=2) , we get
⇒13y=182
⇒y= 182 =14
13
Put y=14 in (1)
2x+3y=92
⇒2x+3×14=92
⇒2x=92−42=50
∴x= 50 =25
2
∴x=25 and y=14