The sum of twice the cost of a box biscuits and the cost of a box chocolates is $8.00. The difference between the cost of box of chocolates and the box of biscuits is $1.00. Find the cost of each.
Answers
Answer:
The cost of a box biscuits = $3.00
The cost of a box chocolates = $2.00
Step-by-step explanation:
Let the cost of a box biscuits be 'x'
and Let the cost of a box chocolates be 'y'
ATQ
2x + y = $8.00 --(1)
x - y = $1.00 --(2)
Equation (1) + Equation (2)
2x + y + x - y = $8.00 + $1.00
3x = $9.00
x = $3.00
=> y = $2.00
HOPE IT HELPS YOU
Given :- The sum of twice the cost of a box biscuits and the cost of a box chocolates is $8.00. The difference between the cost of box of chocolates and the box of biscuits is $1.00.
To Find :- The cost of each box ?
Solution :-
Case 1) :- cost of box of chocolates > cost of of box of biscuits .
Let us assume that, the cost of box of chocolates is $x and the box of biscuits is $y where x > y .
according to first statement,
→ Twice the cost of a box of biscuits + cost of a box of chocolates = $ 8.00
→ 2 × y + x = 8
→ x + 2y = 8 ------------ Equation (1)
according to first statement,
→ cost of box of chocolates - cost box of biscuits = $ 1.00
→ x - y = 1 -------------- Equation (2)
subtracting Equation (2) from Equation (1),
→ (x + 2y) - (x - y) = 8 - 1
→ x - x + 2y + y = 7
→ 3y = 7
→ y = (7/3) = $ 2.33
putting value of y in Equation (2),
→ x - (7/3) = 1
→ x = 1 + (7/3)
→ x = (10/3) = 3.33
therefore, the cost of box of chocolates is $ 3.33 and the cost of box of biscuits is $ 2.33 .
Case 2) :- cost of box of biscuits > cost of of box of chocolates .
Let us assume that, the cost of box of chocolates is $x and the box of biscuits is $y where y > x .
So,
→ x + 2y = 8 ------------ Equation (1)
→ y - x = 1 ------------ Equation (2)
adding Equation (1) and Equation (2),
→ (x + 2y) + (y - x) = 8 + 1
→ x - x + 2y + y = 9
→ 3y = 9
→ y = 3
putting value of y in Equation (2),
→ 3 - x = 1
→ x = 3 - 1
→ x = 2
therefore, the cost of box of chocolates is $ 2.00 and the cost of box of biscuits is $ 3.00 .
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