Question

The sum of twice the first & thrice the second is 92 & four times the exceeds 7times the second by 2 then number are

Answer 1

Answer:

x = 25 & y = 14

Step-by-step explanation:

Let the first number be x.

Let the second number be y.

Then according to question

4x - 7y = 2 ...(i)

Also 2x + 3y = 92....(ii)

Now from (ii) we have

2x = 92 - 3y

Then 4x = 2×(92 - 3y)

4x = 184 - 6y

Now we substitute

4x for 184 - 6y in equation (i)

184 - 6y - 7y = 2

=> -13y = 2 - 184

=> -13y = -182

=> y = -182/-13

=> y = 14

Now we substitute

y for 14 in equation (ii)

2x + 3×14 = 92

=> 2x = 92 - 42

=> 2x = 50

=> x = 25

Hence after solving equation (i) and (ii) we get

x = 25 & y = 14

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