The sum of twice the first and thrice the second is 92 and four times the first exceeds seven times the second by 2, then find the numbers.
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Answer:
25 and 14
Step-by-step explanation:
4x+6y=184
4x-7y=2
( 4x+6y=184)-(4x-7y=184)=(13y=182)
y=14
4x=2+7y=2+7*14=2+98=100
x=25
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