Question

the sum of two 3 digits numbers is 684 HCF 57 and LCM is x. then sum of x digits​

Answer 1

Answer:

hi

Step-by-step explanation:

hi Everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii everyone hiii

Answer 2

The required sum of digit is 24.

Step-by-step explanation:

Consider the provided information.

It is given that the HCF of two numbers = 57

Thus, the numbers are multiples of 57

Let, the numbers be 57x and 57y, where x and y are prime to each other.

It is given that there sum is 684.

57x + 57y = 684

x + y = 12

Required possible pair of values of x and y which are prime to each other are (1, 11) and (5, 7).

For (1, 11) the required pairs of numbers are:

{57 × 1 = 57 and 57 × 11 = 627}

For  (5, 7)the required pairs of numbers are:

{57 × 5 = 285 and 57 × 7 = 399}

Since, it is given that the numbers are 3 digit number.

Thus the required numbers are 285 and 399.

The LCM of 285 and 399:

285 = 5 × 57

399 =  7 × 57

LCM of the numbers are 5 × 7 × 57 = 1995

The sum of x digits is: 1+9+9+5=24

Hence, the required sum of digit is 24.

#Learn more

Find HCF×LCM OF 26×91 and check hcf=lcm​

https://brainly.in/question/9223663