The sum of two angels of a triangle is 116° and their different is 24 find the measure of each angel of the triangle
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Answered by
6
Let angles are x and y
Their sum = 116°
x + y = 116 -----1equation
Their difference = 24
x - y = 24 -----2equation
On adding both equations, we get,
2x = 140
x = 70°
Substituting the value of x in 1equation,
x + y = 116
70 + y = 116
y = 116 - 70
y = 46°
Angle x = 70
Angle y = 46
We know, sum of all angles of a triangle = 180
70 + 46 + third angle = 180
116 + third angle =180
Third angle = 180 - 116
Third angle = 64°
Their sum = 116°
x + y = 116 -----1equation
Their difference = 24
x - y = 24 -----2equation
On adding both equations, we get,
2x = 140
x = 70°
Substituting the value of x in 1equation,
x + y = 116
70 + y = 116
y = 116 - 70
y = 46°
Angle x = 70
Angle y = 46
We know, sum of all angles of a triangle = 180
70 + 46 + third angle = 180
116 + third angle =180
Third angle = 180 - 116
Third angle = 64°
vinod000001:
sorry but answer is 46
Answered by
4
∠A + (∠B + ∠C) = 180°
∠A + 116° = ∠180°
∠A = 180° - 116°
∠A = 64
hope it's help you
∠A + 116° = ∠180°
∠A = 180° - 116°
∠A = 64
hope it's help you
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