Question

The sum of two angkes of a triangle is 80° and their difference is 20°.Find all the angles.

Answer 1

let the two angles be x and y
x+y = 80
x-y= 20
adding the two equations above
2x = 100
x= 50
y = 30 ... so the third angle will be 180 - 80 = 100(angle sum property of ∆)

hence angles are 50,30 n 100.
hope this will help

Answer 2

@
let the angles be /_A & /_B &/_C
/_A+/_B+/_C=180°(sum of interior angles of ∆)
80°+/_C=180°
/_C= 180°-80°
/_C=100°
≈≈≈≈≈≈≈
/_A-/_B= 20°
/_A=20°+/_B
≈≈≈≈≈≈≈
20°+/_B+/_B+100°=180°
2/_B+120°=180°
2/_B= 180°-120°= 60°
/_B= 60°/2
/_B= 30°
≈≈≈≈≈≈≈
/_A+/_B+/_C= 180°
/_A=180°-130°
/_A=50°
@:-)