the sum of two angle of a triangle is 116 degree and their difference is 24 degree find the measure of each angle of a triangle
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Answer:
Let us consider the sum of two angles as ∠A+∠B=116
∘
and the difference can be written as ∠A−∠B=24
∘
We know that the sum of all the angles in a triangle is 180
∘
.
So we can write it as
∠A+∠B+∠C=180
∘
By substituting ∠A+∠B=116
∘
in the above equation
116
∘
+∠C=180
∘
On further calculation
∠C=180
∘
−116
∘
By subtraction
∠C=64
∘
It is given that ∠A−∠B=24
∘
It can be written as ∠A=24
∘
+∠B
Now by substituting ∠A=24
∘
+∠Bin∠A+∠B=116
∘
∠A+∠B=116
∘
24
∘
+∠B+∠B=116
∘
On further calculation
24
∘
+2∠B=116
∘
By subtraction
2∠B=116
∘
−24
∘
2∠B=92
∘
By division
∠B=
2
92
∠B=46
∘
By substituting ∠B=46
∘
in ∠A=24
∘
+∠B
We get
∠A=24
∘
+46
∘
By addition
∠A=70
∘
Therefore, ∠A=70
∘
,∠B=46
∘
and ∠C=64
∘
.
Step-by-step explanation:
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