Question

the sum of two angle of a triangle is equal to third angle if the difference of the two angles is 50 degree then third angle is

Answer 1

Let one of the angles be y.

Therefore, other angle=(y-50°)

Let the 3rd angle be z.

According to question,

z=y+(y-50°)

We have, by triangle sum theorem,

y+(y-50°)+z=180°

=>y+(y-50°)+y+(y-50°)=180°

=>y+y-50°+y+y-50°=180°

=>4y-100°=180°

=>4y=180°+100°

=>4y=280°

=>y=280°÷4=70°

Therefore, the angles are

y=70°

y-50°=70°-50°=20°

y+(y-50°)=70°+20°=90°

Answer 2

Answer: Third angle is 90°

Step-by-step explanation:

Let the angles be a,b & c.

ATQ,

c=a+b

& a-b=50° =>a=50°+b

Now,

a+b+c=180° [Angle Sum Property of Triangle]

=>50°+b+b+a+b=180°

=>50°+b+b+50°+b+b=180°

=>100°+4b=180°

=>4b=180°-100°

=>4b=80°

=>b=80°÷4

=>b=20°

a=50°+b=50°+20°=70°

c=a+b=70°+20°=90°

THEREFORE, third angle=c=90°