The sum of two angles of a quadrilateral is 120° the other two angles are equal find the measure of each angle
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Answer:
let the quadrilateral be ABCD
acq
A+B=120
ac to the ASP
A+B+C+D=36O DEGREES
so,
60+60+C+D=360 DEGREES
C+D =360-120
C+D=240/2 (AS OPPOSITE SIDES ARE EQUAL IN A QUADRILATERAL)
C+D=120
∴ A = 60 DEGREES
B = 60 DEGREES
C = 120 DEGREES
D = 120 DEGREES CHECK=
SUM OF ALL ANGLES = 360
60
+60
+120
+120
360
Step-by-step explanation:
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