the sum of two angles of a triangle is 116 degree and their difference is 24 degree find the measure of each angle of the triangle
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let the two unknown angles be x and y
x+y=116 (equation 1)
x-y=4 (equation 2)
using elimination method
subtract equation 2 from 1
(x-x)(y+y)=116-4
2y=112
y=112/2=56
y=56
since x+y=116
x=60
And sum of all angles in a triangle is 180 degrees
x+y+z=180(z is the third angle)
60+56+z=180
z=180-60+56
z=180-116
z=64
x+y=116 (equation 1)
x-y=4 (equation 2)
using elimination method
subtract equation 2 from 1
(x-x)(y+y)=116-4
2y=112
y=112/2=56
y=56
since x+y=116
x=60
And sum of all angles in a triangle is 180 degrees
x+y+z=180(z is the third angle)
60+56+z=180
z=180-60+56
z=180-116
z=64
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