the sum of two angles of a triangle is 116° and there difference is 24°. find all the angles of the triangle.
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Let one of the angle be X and other be Y
X+Y=116
X-Y=24
Adding both equations we get 2X=140
Therefore,X=70 and Y=46
Let the third angle be Z
X+Y+Z=180
70+46+Z=180
Z=180-116
=64
X+Y=116
X-Y=24
Adding both equations we get 2X=140
Therefore,X=70 and Y=46
Let the third angle be Z
X+Y+Z=180
70+46+Z=180
Z=180-116
=64
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