Question

The sum of two angles of a triangle is 1200 and their difference is 200 . Find all the three angles in a triangle​

Answer 1

Answer:

Answer

Consider a △ABC,

then according to the given condition we have:

∠A+∠B=80

o

and ∠A−∠B=20

o

⇒2∠A=100

o

⇒∠A=50

o

⇒∠B=30

o

Using the sum of all the angles of the triangle is 180

o

We have: ∠A+∠B+∠C=180

o

⇒50

o

+30

o

+∠C=180

o

⇒∠C=100

o

Hence ∠A=50

o

, ∠B=30

o

and ∠C=100

o

Answer 2

Answer:

Consider a △ABC,

then according to the given condition we have:

∠A+∠B=80

o

and ∠A−∠B=20

o

⇒2∠A=100

o

⇒∠A=50

o

⇒∠B=30

o

Using the sum of all the angles of the triangle is 180

o

We have: ∠A+∠B+∠C=180

o

⇒50

o

+30

o

+∠C=180

o

⇒∠C=100

o

Hence ∠A=50

o

, ∠B=30

o

and ∠C=100

o