The sum of two angles of a triangle is 120ð and their difference is 20ð . find all the three angles
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here you go ☆☆
▪let third angle = x
sum of all angles of triangle = 180°
▪120 + x = 180
▪x = 180-120
▪ 60°
▪let first angle be a and second angle be b
▪a+b= 120--------
▪a-b=20--------ii
▪subtracting ii from I
▪ a+b= 120
▪a-b=20
▪2a= 100
▪a= 100/2
▪a= 50
therefore
▪ b = 120-50
▪ 70
three angle are:-
60°, 50° ,70°
hope it helps you .......
▪let third angle = x
sum of all angles of triangle = 180°
▪120 + x = 180
▪x = 180-120
▪ 60°
▪let first angle be a and second angle be b
▪a+b= 120--------
▪a-b=20--------ii
▪subtracting ii from I
▪ a+b= 120
▪a-b=20
▪2a= 100
▪a= 100/2
▪a= 50
therefore
▪ b = 120-50
▪ 70
three angle are:-
60°, 50° ,70°
hope it helps you .......
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3
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