Question

The sum of two angles of a triangle is 80 and their difference is 20. Find all the angles of the triangle

Answer 1

let the two angles be x and y 

then

ATQ

x+y = 80

x-y= 20

adding the two equations above we get 2x = 100 this means x= 50 and y = 30 ... so the third angle will be 180 - (80) = 100


therefore the three angles are 50 30 and 100

HOPE IT HELPS YOU

Answer 2

Let the three required angles be A,B and C.
According to quest;
A+B=80°_equation 1
& A-B=20°_equation 2
Adding 1 and 2;we get;
2A=100°
A=50°
Put A=50° in equation 1;
Now;we get;
B=30°
Now;A+B+C=180°(Angle sum property of triangle)
50°+30°+C=180°
C+80°=180°
C=100°
Therefore;The required three angles are;
A=50°,B=30°andC=100°.
I hope this would be helpful.