the sum of two angles of a triangle is 80° and the difference is 20°. find all the angles of triangle.
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Let the two angles be x and y.
x + y = 80°
x - y = 20°
2x = 100°
x = 100/2
x = 50°
x + y = 80°
50° + y = 80°
y = 80° - 50°
y = 30°
Let the other angle be z.
x + y + z = 180°(angle sum property of ∆)
50° + 30° + z = 180°
80° + z = 180°
z = 180° - 80°
z = 100°
Ans: The angles of the triangle are 50° , 30° and 100°.
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