The sum of two angles of a triangle is 80° and their is 20°.Find all the angles.
Adithya1234:
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Answered by
2
Let the angles be x, y and z then
x+y+z=180°
A/Q-
Case I: x+y=80°
x=80°-y------------(1)
Case II: x-y=20°
x=20°+y---------(2)
On comparing equation (1) and (2)
80°-y=20°+y
⇒2y=80°-20°
y=60°/2
y=30°
Then x=80°-30°
x=50°
We know that x+y+z=180°
80°+z=180°
z=180°-80°
z=100°
So, The angles are 30°, 50° and 100°.
x+y+z=180°
A/Q-
Case I: x+y=80°
x=80°-y------------(1)
Case II: x-y=20°
x=20°+y---------(2)
On comparing equation (1) and (2)
80°-y=20°+y
⇒2y=80°-20°
y=60°/2
y=30°
Then x=80°-30°
x=50°
We know that x+y+z=180°
80°+z=180°
z=180°-80°
z=100°
So, The angles are 30°, 50° and 100°.
Answered by
0
The sum of two angles is . We know that all the three angles of a triangle adds up to 180. One of them is 20. So subtract.
80-20=60
180-80=100
Therefore the angles are 20,60 and 100.
80-20=60
180-80=100
Therefore the angles are 20,60 and 100.
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