The sum of two angles of a triangle is 80°and difference is 20°. Find all angles of triangle.
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HEYA!
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Let the Angles be X° and Y° respectively.
ACCORDING TO THE GIVEN QUESTION:-
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X + Y = 80 °
X - Y = 20°
Solving the two equations by Elimination Method ,
2X = 100
X = 50°
Put X = 50 in the equation ,
50 + Y = 80
Y = 30°
We can now find the third angle by Angle Sum Property .
Sum of Angles of a Triangle = 180
50° + 30° + Z = 180
Z =100°
Hence the Angle are 30° , 50° and 100°
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--------
Let the Angles be X° and Y° respectively.
ACCORDING TO THE GIVEN QUESTION:-
===================================
X + Y = 80 °
X - Y = 20°
Solving the two equations by Elimination Method ,
2X = 100
X = 50°
Put X = 50 in the equation ,
50 + Y = 80
Y = 30°
We can now find the third angle by Angle Sum Property .
Sum of Angles of a Triangle = 180
50° + 30° + Z = 180
Z =100°
Hence the Angle are 30° , 50° and 100°
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