Question

the sum of two angles of a triangle os 80 degree and their difference is 20 degree. find all angles of the triangle.​

Answer 1

Step-by-step explanation:

as we know the sum of all angles of triangle is 180°

let first angle = X

second angle be y

third angle be z

acc.to question

the sum of two angles is 80

let X and y be those angle so, X + y = 80 ..........1.

the difference of these two angles is 20 as given

so ,. X - y = 20 ............2.

solving 1.and 2.

x+ y = 80

X - y = 20

changing signs by the use of elimination method , X will be cut down , y will change to + become 2y and +20 changes to - 20 and 80-20 = 60

we get , 2y = 60

y = 60/2

y = 30

now putting y in 1.

x + y = 80

X + 30 = 80

X = 80-30

x = 50

putting X and y in

x + y + z = 180 ..........as said earlier

50 + 30 + z = 180

80 + z = 180

z = 180 - 80

z = 100

all angles X = 50 , y = 30 and z = 100

to prove it

x + y + z = 180

50+ 30 + 100 = 180

180 = 180

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