the sum of two angles of triangle is 80 degree and their difference is 20 degree find all the angles of triangle
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Let a,b,c be the angles of triangle
Given a+b=80&a-b=20
Add both
(a+b)+(a-b)=80+20
2a=100
a=50
b=80-50=30
c=180-(50+30)=180-80
=100
Angles of the triangle are 100,50&30
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Answered by
3
Answer:
Step-by-step explanation:
x+y=80
x=y+20
x=80-y
20+y=80-y
2y=60
y=30
x+30=80
x=50
80+z=180
z=100
Angles:
x=50
y=30
z=100
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