Question

The sum of two consectutive positive integers is 11 less than their product.
find the integers.

Answer 1

Step-by-step explanation:

Let the integers be:

x and x + 1

x + x + 1 = (x)×(x +1) - 11

2x + 1 = x^2 + x - 11

x^2 - x - 12 = 0

x^2 - 4x + 3x -12 = 0

x(x-4) + 3(x-4) = 0

(x-4)(x+3) = 0

x = 4 or x = -3 (x cannot be -3)

x = 4

x+1 = 5

TWO POSITIVE INTEGERS ARE 4 AND 5

HOPE IT HELPS