The sum of two consecutive even integers is 46.Find the integers.
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Answers
Answered by
1
Let first even integer = x
then the consecutive even integer becomes = x + 2
we are given
x + x + 2 = 46
2x + 2 = 46
2x = 44
x = 44/2 = 22
First even integer = 22, and consecutive even integer = 24
Answer 22, 24
Answered by
21
Heya!
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▪Let the two integers be x and ( x + 2 ) respectively .
↪According to the given question ->
===============================
=> x + x + 2= 46
=> 2x + 2 = 46
=> 2x = 44
=> x = 22
▪Hence the Integers are 22 and ( 22 + 2 ) = 24 ✔
=============================================================
--------
============================================================
▪Let the two integers be x and ( x + 2 ) respectively .
↪According to the given question ->
===============================
=> x + x + 2= 46
=> 2x + 2 = 46
=> 2x = 44
=> x = 22
▪Hence the Integers are 22 and ( 22 + 2 ) = 24 ✔
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