the sum of two consecutive integer in 49.find the number
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Answered by
13
let the first integer be X
thus the second integer will be X+1
because they are consecutive
it is given that the sum of the consecutive integers is 49
thus, X+(X+1)=49
2x+1=49
2x=49-1
2x=48
X=48÷2
X=24
X+1=24+1=25
therefore the two integers are 24 and 25
checking:
24+25=49
thus the second integer will be X+1
because they are consecutive
it is given that the sum of the consecutive integers is 49
thus, X+(X+1)=49
2x+1=49
2x=49-1
2x=48
X=48÷2
X=24
X+1=24+1=25
therefore the two integers are 24 and 25
checking:
24+25=49
Answered by
7
Let n and n+1 be the 2 consecutive integers.
so, n+ (n+1) = 49
=>2n+1=49
=>2n= 49-1
=> 2n=48
=> n=48÷2
=> n=24
and n+1=25
So, the numbers are 24 and 25.
so, n+ (n+1) = 49
=>2n+1=49
=>2n= 49-1
=> 2n=48
=> n=48÷2
=> n=24
and n+1=25
So, the numbers are 24 and 25.
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