Question

The sum of two consecutive integer is 49.find the numbers
​

Answer 1

Answer:

Let the integers be ...... n, (n+1)

n+(n+1) = 49

2n + 1 = 49

2n = 49-1

2n = 48

n = 48/2

n = 24

Therefore, the numbers are 24, 25

Answer 2

Answer:

Let one number be x.

Then,the next consecutive number is x+1

Given: sum of 2 consecutive integers = 49

$x + x + 1 = 49 \\ 2x + 1 = 49 \\ 2x49 - 1 \\ 2x = 48 \\ x = \frac{48}{2} = 24 \\ since \: x = 24 \: therefore \: x + 1 = 24 + 1 = 25$

✅Hence the required, numbers are 24 and 25