The sum of two consecutive integer is three times their different. What is the larger number?
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The difference of two consecutive integers is always going to be 1. So the sum must be 3. And there are really only two consecutive integers whose sum is 3: 1 and 2. The larger number is 2, so that’s your answer.
But if you want to do this the hard way:
Let a be the larger integer and let a−1 be the smaller integer.
Their sum is a+(a−1)=2a−1
Their difference is a−(a−1)=1
From the problem, we know that 2a−1=3(1)
2a−1=3
2a=4
a=2
Step-by-step explanation:
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