Question

the sum of two consecutive multilpkes of 7 is 77.find them

Answer 1

let first multiple be x
then another multiple is x+7

therefore
x+(x+7)=77
2x+7=77
2x=77-7
2x=70
x=35


therefore first multiple is 35
and the second is 35+7
=42

Answer 2

Answer :

Let us take the two consecutive multiples of 7 are 7n and 7(n + 1)

By the given condition,

7n + 7(n + 1) = 77

or, n + n + 1 = 11, dividing both sides by 7

or, 2n = 11 - 1

or, 2n = 10

or, n = 5

Therefore, the two consecutive multiples of 7 are (7 × 5) and {7 × (5 + 1)},

i.e., 35 and 42

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