Question

The sum of two consecutive multiple of 8 is 136.find the numbers​

Answer 1

Step-by-step explanation:

let 2 multiples of 8 be

8x

8(x+1)

so

8x+8(x+1)=136. .......(given)

16x+8=136

16x=128

x=8

so numbers are 8×8=64

and 8×9=72

so u can check now 64+72=136

Answer 2

Answer:

For this question we will find the two consecutive numbers which is multiple of $8$ using their sum is $136$. Final Answer: That two numbers are, $64$ and $72$.

Step-by-step explanation:

We consider that two consecutive numbers are $x$ and $x+1$.

which is multiple of $8$. It should be written as,

two consecutive numbers are $8x$ and $8(x+1)$.

Sum of the two consecutive numbers which is multiple of $8$ is $136$.

That is,     $8x+8(x+1)=136$

                $8x+(8x+8)=136$

Now add the $x$ terms and constant in the above equation. It can be written as,

                              $16x+8=136$

                                   $16x=136-8$

                                   $16x=128$

                                      $x=\frac{128}{16}$

                                      $x=8$

Using this $x$ value we can find that two consecutive numbers.

First number is,          $8x=8(8)$

                                    $8x=64$

Next number is,  $8(x+1)=8(8+1)$

                            $8(x+1)=8(9)$

                            $8(x+1)=72$