the sum of two consecutive multiples of 10 is 210. find the smaller multiple.
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let the two consecutive multiples of 10 be x and x+10
the sum of two consecutive multiples of 10 is 210
x+x+10 = 210
2x+10 = 210
2x = 210-10
2x = 200
x = 200/2
x = 100
smallest multiple = x = 100
largest multiple = x+10 = 100+10 = 110
hope it helps...
the sum of two consecutive multiples of 10 is 210
x+x+10 = 210
2x+10 = 210
2x = 210-10
2x = 200
x = 200/2
x = 100
smallest multiple = x = 100
largest multiple = x+10 = 100+10 = 110
hope it helps...
toshani:
thanks a lot
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