Question

The sum of two consecutive multiples of 10 is 210. the smaller multiple is 110,120,100,80

Answer 1

Answer:

The smaller multiple is 100 as 100 +110=210

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Step-by-step explanation:

Answer 2

Answer:

100

Step-by-step explanation:

Sum of two numbers=number a+number b

Here, sum=210 and we have to find smaller number

Let number a>number b

so, we need options and value of number a

number a=210-number b

Let us put options as values of number b

a) a=210-110=100

Not satisfying our needs

b) a=210-120=90

Not satisfying our needs

c)a=210-100=110

Satisfying our needs

d)a=210-80=130

Satisfying our needs

Now we got 100 and 80 as the answer.

We did not include one statement that the two numbers (a and b) are two consecutive multiples of 10.

So, we will find one of these two numbers which-

1) when doubled and then added to 10 gives 210.

OR

2) when added to itself+10 gives 210.

I am choosing method 1

c) 2*100+10=200+10=210

Satisfying our needs

d) 2*80+10=160+10=170

Not satisfying our needs

Hence the smaller multiple is- c) 100

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