Question

The sum of two consecutive multiples of 12 is 300. Find the smaller multiple​

Answer 1

Answer:

Let the multiples of 7x&7(x+1)

(7x)

2

+(7(x+1))

2

=637

⇒49x

2

+49(x+1)

2

=637

⇒x

2

+(x+1)

2

=13

⇒x

2

+x

2

+1+2x−13=0

⇒2x

2

+2x−12=0

⇒x

2

+x−6=0

⇒(x+3)(x−2)=0

so x=-3 or x=2

no s= -14,-21 no s=14,21

hope it will help you

Answer 2

Answer:

Let the three consecutive multiples of 11 are 11x, 11x+11 and 11x+22

Their sum is 363

11x+11x+11+11x+22=363

33x+33=363

33x=363−33

33x=330

x=

33

330

x=10

First multiple =11x=11×10=110

Second multiple =11x+11=110+11=121

Third multiple =11x+22=110+22=132

Step-by-step explanation:

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