Question

the sum of two consecutive multiples of 16 is 208.find three multiples

Answer 1

Answer:

Step-by-step explanation:

Let first be (x)

Second be(x+16)

Third be (x+32)

Acc to que

X+x+16+x+32=208

Answer 2

let two consecutive terms of 16 be 16(x) and 16(x+1)
16x +16x + 16 = 208
32x = 208-16
X =6
verification
16×6= 96
16 ( 7) = 112
96+ 112= 208