The sum of two consecutive multiples of 2 is 18.find the numbers
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Answered by
17
Let consecutive multiple of 2 are 2x , ( 2x +2) .
A/c to question ,
sum of consecutive multiple of 2 = 18
2x + (2x + 2) = 18
4x +2 = 18
4x = 16
x = 4
hence ,
number are , 2x = 2× 4 = 8
(2x +2) = 2×4 +2 = 10
8 and 10 are the consecutive multiple of 2
A/c to question ,
sum of consecutive multiple of 2 = 18
2x + (2x + 2) = 18
4x +2 = 18
4x = 16
x = 4
hence ,
number are , 2x = 2× 4 = 8
(2x +2) = 2×4 +2 = 10
8 and 10 are the consecutive multiple of 2
Answered by
12
Hey !
Let consecutive multiples of 2 be 2x , ( 2x +2) .
sum of the consecutive multiples = 18
That is ,
2x + 2x + 2 = 18
4x + 2 = 18
4x = 18 - 6
x = 16/4
x = 4
Therefore ,
The numbers are :-
2x = 2× 4 = 8
2x +2 = 2×4 +2 = 10
8 and 10 are the two consecutive multiples of two .
Let consecutive multiples of 2 be 2x , ( 2x +2) .
sum of the consecutive multiples = 18
That is ,
2x + 2x + 2 = 18
4x + 2 = 18
4x = 18 - 6
x = 16/4
x = 4
Therefore ,
The numbers are :-
2x = 2× 4 = 8
2x +2 = 2×4 +2 = 10
8 and 10 are the two consecutive multiples of two .
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